(5x+4)(4x^2+2x+7)=

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Solution for (5x+4)(4x^2+2x+7)= equation:


Simplifying
(5x + 4)(4x2 + 2x + 7) = 0

Reorder the terms:
(4 + 5x)(4x2 + 2x + 7) = 0

Reorder the terms:
(4 + 5x)(7 + 2x + 4x2) = 0

Multiply (4 + 5x) * (7 + 2x + 4x2)
(4(7 + 2x + 4x2) + 5x * (7 + 2x + 4x2)) = 0
((7 * 4 + 2x * 4 + 4x2 * 4) + 5x * (7 + 2x + 4x2)) = 0
((28 + 8x + 16x2) + 5x * (7 + 2x + 4x2)) = 0
(28 + 8x + 16x2 + (7 * 5x + 2x * 5x + 4x2 * 5x)) = 0
(28 + 8x + 16x2 + (35x + 10x2 + 20x3)) = 0

Reorder the terms:
(28 + 8x + 35x + 16x2 + 10x2 + 20x3) = 0

Combine like terms: 8x + 35x = 43x
(28 + 43x + 16x2 + 10x2 + 20x3) = 0

Combine like terms: 16x2 + 10x2 = 26x2
(28 + 43x + 26x2 + 20x3) = 0

Solving
28 + 43x + 26x2 + 20x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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